A can complete a piece of work in 10 days,whi | vedclass

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(B) Work done by $A$ in $1$ day $= 1/10$.Work done by $B$ in $1$ day $= 1/15$.Work done by $(A+B)$ in $5$ days $= 5 	imes (1/10 + 1/15) = 5 	imes (3

Vedclass · Accepted Answer

$225, 150, 75$

Vedclass · Answer

(B) Work done by $A$ in $1$ day $= 1/10$.Work done by $B$ in $1$ day $= 1/15$.Work done by $(A+B)$ in $5$ days $= 5 	imes (1/10 + 1/15) = 5 	imes (3+2)/30 = 5 	imes (5/30) = 5/6$.Remaining work $= 1 - 5/6 = 1/6$.This remaining work is done by $C$ in $2$ days.Since wages are distributed in the ratio of work done,we calculate the work done by each person:Work done by $A = 5/10 = 1/2 = 3/6$.Work done by $B = 5/15 = 1/3 = 2/6$.Work done by $C = 1/6$.The ratio of work done by $A:B:C = 3/6 : 2/6 : 1/6 = 3:2:1$.Total parts $= 3+2+1 = 6$.$A$'s share $= (3/6) 	imes 450 = Rs. 225$.$B$'s share $= (2/6) 	imes 450 = Rs. 150$.$C$'s share $= (1/6) 	imes 450 = Rs. 75$.

$A$ can complete a piece of work in $10$ days,while $B$ alone can complete it in $15$ days. They work together for $5$ days and the rest of the work is done by $C$ in $2$ days. If they receive $Rs. 450$ for the whole work,how should they divide the money? (in $Rs.$)

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