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(C) Part of work done by $A$ in $1 \, day = \frac{1}{16}$.Part of work done by $B$ in $1 \, day = \frac{1}{12}$.Part of work done by $A, B$ and $C$ to

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$9\frac{3}{5}$

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(C) Part of work done by $A$ in $1 \, day = \frac{1}{16}$.Part of work done by $B$ in $1 \, day = \frac{1}{12}$.Part of work done by $A, B$ and $C$ together in $1 \, day = \frac{1}{4}$.To find the work done by $C$ alone in $1 \, day$,we subtract the work done by $A$ and $B$ from the total work done by all three:Work done by $C$ in $1 \, day = \frac{1}{4} - (\frac{1}{16} + \frac{1}{12})$.Finding a common denominator for $4, 16,$ and $12$,which is $48$:Work done by $C$ in $1 \, day = \frac{12}{48} - (\frac{3}{48} + \frac{4}{48}) = \frac{12 - 7}{48} = \frac{5}{48}$.Therefore,$C$ alone can complete the job in $\frac{48}{5} = 9\frac{3}{5} \, days$.

$A$ can lay railway track between two given stations in $16 \, days$ and $B$ can do the same job in $12 \, days$. With the help of $C$,they did the job in $4 \, days$ only. Then $C$ alone can do the job in (in $days$)

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