12 % of Kaushal's monthly salary is equal to | vedclass

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(D) Suresh's annual salary $= Rs.\, 1,08,000$.Suresh's monthly salary $= \frac{1,08,000}{12} = Rs.\, 9,000$.Since Suresh's monthly salary is half of N

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$24000$

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(D) Suresh's annual salary $= Rs.\, 1,08,000$.Suresh's monthly salary $= \frac{1,08,000}{12} = Rs.\, 9,000$.Since Suresh's monthly salary is half of Nandini's,Nandini's monthly salary $= 9,000 	imes 2 = Rs.\, 18,000$.Let Kaushal's monthly salary be $K$.According to the problem,$12 \% 	ext{ of } K = 16 \% 	ext{ of } 18,000$.$K 	imes \frac{12}{100} = 18,000 	imes \frac{16}{100}$.$K 	imes 12 = 18,000 	imes 16$.$K = \frac{18,000 	imes 16}{12}$.$K = 1,500 	imes 16 = 24,000$.Thus,Kaushal's monthly salary is $Rs.\, 24,000$.

$12 \%$ of Kaushal's monthly salary is equal to $16 \%$ of Nandini's monthly salary. Suresh's monthly salary is half that of Nandini's monthly salary. If Suresh's annual salary is $Rs.\, 1.08$ lakhs,what is Kaushal's monthly salary in $Rs.$?

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