$10$ years ago, the average age of a family of $4$ members was $24$ $years.$ Two children having been born (with age difference of $2\, years$), the present average age of the family is the same. The present age of the youngest child is (in $years$)

  • A

    $1$

  • B

    $2$

  • C

    $3$

  • D

    $5$

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