Match the reactions in Column-$(I)$ with the type of reaction mechanism in Column-$(II)$.
Column-$(I)$ (Reaction) Column-$(II)$ (Type of Reaction) $(A)$ $\text{Cyclohexene} + Br_2 \xrightarrow{\Delta, uv} \text{3-Bromocyclohexene}$ $(i)$ $\text{Nucleophilic substitution}$ $(B)$ $\text{4-Hydroxybenzyl alcohol} + HCl \xrightarrow{\Delta} \text{4-Hydroxybenzyl chloride}$ $(ii)$ $\text{Electrophilic addition}$ $(C)$ $\text{Cyclohexene} + Br_2 \xrightarrow{CCl_4} \text{1,2-Dibromocyclohexane}$ $(iii)$ $\text{Free radical substitution}$ $(D)$ $\text{Toluene} + Cl_2 \xrightarrow{Fe, \text{dark}} \text{o/p-Chlorotoluene}$ $(iv)$ $\text{Electrophilic aromatic substitution}$
| Column-$(I)$ (Reaction) | Column-$(II)$ (Type of Reaction) |
|---|---|
| $(A)$ $\text{Cyclohexene} + Br_2 \xrightarrow{\Delta, uv} \text{3-Bromocyclohexene}$ | $(i)$ $\text{Nucleophilic substitution}$ |
| $(B)$ $\text{4-Hydroxybenzyl alcohol} + HCl \xrightarrow{\Delta} \text{4-Hydroxybenzyl chloride}$ | $(ii)$ $\text{Electrophilic addition}$ |
| $(C)$ $\text{Cyclohexene} + Br_2 \xrightarrow{CCl_4} \text{1,2-Dibromocyclohexane}$ | $(iii)$ $\text{Free radical substitution}$ |
| $(D)$ $\text{Toluene} + Cl_2 \xrightarrow{Fe, \text{dark}} \text{o/p-Chlorotoluene}$ | $(iv)$ $\text{Electrophilic aromatic substitution}$ |
(A-III, B-I, C-II, D-IV) $(A) \rightarrow (iii)$: Allylic bromination using $Br_2$ under $uv$ light is a free radical substitution reaction.
$(B) \rightarrow (i)$: The replacement of $-OH$ group by $-Cl$ in the benzylic position is a nucleophilic substitution reaction.
$(C) \rightarrow (ii)$: The addition of $Br_2$ across the double bond of cyclohexene is an electrophilic addition reaction.
$(D) \rightarrow (iv)$: The chlorination of toluene in the presence of $Fe$ (Lewis acid) is an electrophilic aromatic substitution reaction.
Therefore,the correct matching is: $(A-iii, B-i, C-ii, D-iv)$.
$(B) \rightarrow (i)$: The replacement of $-OH$ group by $-Cl$ in the benzylic position is a nucleophilic substitution reaction.
$(C) \rightarrow (ii)$: The addition of $Br_2$ across the double bond of cyclohexene is an electrophilic addition reaction.
$(D) \rightarrow (iv)$: The chlorination of toluene in the presence of $Fe$ (Lewis acid) is an electrophilic aromatic substitution reaction.
Therefore,the correct matching is: $(A-iii, B-i, C-ii, D-iv)$.
Explore More
Similar Questions
Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List-$I$ with an appropriate structure from List-$II$ and select the correct answer using the code given below the lists.
List-$I$:
$P$. Pathway $P$
$Q$. Pathway $Q$
$R$. Pathway $R$
$S$. Pathway $S$
List-$II$:
$1$. $C_6H_5CH_2CO_3CH_3$
$2$. $C_6H_5CO_3CH_3$
$3$. $C_6H_5CH_2CO_3C(CH_3)_2CH_2C_6H_5$
$4$. $C_6H_5CO_3C(CH_3)_2C_6H_5$
Codes:
$P \quad Q \quad R \quad S$
$A. 1 \quad 3 \quad 4 \quad 2$
$B. 2 \quad 4 \quad 3 \quad 1$
$C. 4 \quad 1 \quad 2 \quad 3$
$D. 3 \quad 2 \quad 1 \quad 4$
List-$I$:
$P$. Pathway $P$
$Q$. Pathway $Q$
$R$. Pathway $R$
$S$. Pathway $S$
List-$II$:
$1$. $C_6H_5CH_2CO_3CH_3$
$2$. $C_6H_5CO_3CH_3$
$3$. $C_6H_5CH_2CO_3C(CH_3)_2CH_2C_6H_5$
$4$. $C_6H_5CO_3C(CH_3)_2C_6H_5$
Codes:
$P \quad Q \quad R \quad S$
$A. 1 \quad 3 \quad 4 \quad 2$
$B. 2 \quad 4 \quad 3 \quad 1$
$C. 4 \quad 1 \quad 2 \quad 3$
$D. 3 \quad 2 \quad 1 \quad 4$
Identify the product of the above rearrangement reaction.
Difficult
View SolutionWhat happens when a chemical reaction occurs?
Easy
View SolutionWhich of the following statements is $NOT$ correct for heterolysis?
Heterolysis of $C-Cl$ bond produces:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo