Different possible thermal decomposition path | vedclass

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(A) The thermal decomposition of peroxyesters depends on the stability of the radicals formed and the ability of the alkoxy radical $(R'O^{\bullet})$

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(A) The thermal decomposition of peroxyesters depends on the stability of the radicals formed and the ability of the alkoxy radical $(R'O^{\bullet})$ to undergo $\beta$-scission.$1$. $C_6H_5CH_2CO_3CH_3$: The $C_6H_5CH_2^{\bullet}$ radical is stable. The $CH_3O^{\bullet}$ radical cannot undergo $\beta$-scission. Thus,it follows pathway $P$.$2$. $C_6H_5CO_3CH_3$: The $C_6H_5CO_2^{\bullet}$ radical is relatively stable. The $CH_3O^{\bullet}$ radical cannot undergo $\beta$-scission. Thus,it follows pathway $S$.$3$. $C_6H_5CH_2CO_3C(CH_3)_2CH_2C_6H_5$: The $C_6H_5CH_2^{\bullet}$ radical is stable. The alkoxy radical can undergo $\beta$-scission to form a carbonyl compound. Thus,it follows pathway $Q$.$4$. $C_6H_5CO_3C(CH_3)_2C_6H_5$: The $C_6H_5CO_2^{\bullet}$ radical is relatively stable. The alkoxy radical can undergo $\beta$-scission to form a carbonyl compound. Thus,it follows pathway $R$.Matching: $P-1, Q-3, R-4, S-2$. The correct option is $A$.

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