${K_a} = 1.4 \times {10^{ - 5}}$ of propanoic acid. Calculate its $pH$ of $0.1$ $M$ solution.

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$\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.2 \times 10^{-3}, \mathrm{pH}=2.92$

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Base $K _{ b }$
Dimethylamine, $\left( CH _{3}\right)_{2} NH$ $5.4 \times 10^{-4}$
Triethylamine, $\left( C _{2} H _{5}\right)_{3} N$ $6.45 \times 10^{-5}$
Ammonia, $NH _{3}$ or $NH _{4} OH$ $1.77 \times 10^{-5}$
Quinine, ( $A$ plant product) $1.10 \times 10^{-6}$
Pyridine, $C _{5} H _{5} N$ $1.77 \times 10^{-9}$
Aniline, $C _{6} H _{5} NH _{2}$ $4.27 \times 10^{-10}$
Urea, $CO \left( NH _{2}\right)_{2}$ $1.3 \times 10^{-14}$