If $R = 0.082$,write it with its units and state the value with full precision.
(N/A) $(i)$ $R = 0.082 \, L \, atm \, K^{-1} \, mol^{-1}$
$(ii)$ $R = 8.20 \times 10^{-2} \, L \, atm \, K^{-1} \, mol^{-1}$
The value of $R$ with full precision is:
$(iii)$ $R = 8.20578 \times 10^{-2} \, L \, atm \, K^{-1} \, mol^{-1}$
$(ii)$ $R = 8.20 \times 10^{-2} \, L \, atm \, K^{-1} \, mol^{-1}$
The value of $R$ with full precision is:
$(iii)$ $R = 8.20578 \times 10^{-2} \, L \, atm \, K^{-1} \, mol^{-1}$
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