Which of the following species,O_2^- or O_2^{ | vedclass

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(A) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of $O_2$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \s

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$O_2^-$

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(A) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of $O_2$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. For $O_2^-$,the bond order is $\frac{10 - 7}{2} = 1.5$. For $O_2^{2-}$,the bond order is $\frac{10 - 8}{2} = 1.0$. Therefore,$O_2^-$ has a higher bond order than $O_2^{2-}$.

Which of the following species,$O_2^-$ or $O_2^{2-}$,has a higher bond order?

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