The dipole moment mu of CH_4 and CCl_4 is 0. | vedclass

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(C) Both $CH_4$ and $CCl_4$ have a dipole moment $\mu = 0$,which indicates that they are non-polar molecules.In these molecules,the central atom $(C)$

Vedclass · Accepted Answer

Tetrahedral

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(C) Both $CH_4$ and $CCl_4$ have a dipole moment $\mu = 0$,which indicates that they are non-polar molecules.In these molecules,the central atom $(C)$ is $sp^3$ hybridized.The four bonds are arranged symmetrically in space to minimize electron-pair repulsion.This arrangement results in a tetrahedral geometry with a bond angle of $109^{\circ} 28^{\prime}$.Because of this high symmetry,the individual bond dipoles cancel each other out,resulting in a net dipole moment of zero.

The dipole moment $\mu$ of $CH_4$ and $CCl_4$ is $0$. Predict their shapes. Provide the correct shape with reasons.

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