Identify the molecule which contains a lone p | vedclass

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(D) To identify the molecule with a lone pair on the sulphur atom,we examine the oxidation state and bonding of sulphur in each molecule:$1$. In $H_2S

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$H_2SO_3$

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(D) To identify the molecule with a lone pair on the sulphur atom,we examine the oxidation state and bonding of sulphur in each molecule:$1$. In $H_2SO_5$ (peroxymonosulphuric acid),$H_2S_2O_8$ (peroxydisulphuric acid),and $H_2S_2O_7$ (pyrosulphuric acid),the sulphur atom is in the $+6$ oxidation state. In this state,sulphur uses all its valence electrons for bonding,leaving no lone pair.$2$. In $H_2SO_3$ (sulphurous acid),the sulphur atom is in the $+4$ oxidation state. The electronic configuration of sulphur is $[Ne] 3s^2 3p^4$. In $H_2SO_3$,sulphur forms two $S-OH$ bonds and one $S=O$ double bond. This utilizes $4$ valence electrons,leaving one lone pair on the sulphur atom.Therefore,$H_2SO_3$ is the correct molecule.

Identify the molecule which contains a lone pair of electrons on the sulphur atom.

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