P_4O_6 reacts with water according to the equ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Molecular mass of $P_4O_6 = 220 \ g/mol$. Moles of $P_4O_6$ dissolved = $\frac{1.1 \ g}{220 \ g/mol} = 0.005 \ mol$. According to the reaction $P_

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(B) Molecular mass of $P_4O_6 = 220 \ g/mol$. Moles of $P_4O_6$ dissolved = $\frac{1.1 \ g}{220 \ g/mol} = 0.005 \ mol$. According to the reaction $P_4O_6 + 6H_2O 	o 4H_3PO_3$,$1 \ mol$ of $P_4O_6$ produces $4 \ mol$ of $H_3PO_3$. Moles of $H_3PO_3$ produced = $4 	imes 0.005 = 0.02 \ mol$. $H_3PO_3$ is a dibasic acid,so it reacts with $NaOH$ as: $H_3PO_3 + 2NaOH 	o Na_2HPO_3 + 2H_2O$. Moles of $NaOH$ required = $2 	imes 	ext{moles of } H_3PO_3 = 2 	imes 0.02 = 0.04 \ mol$. Volume of $NaOH$ solution = $\frac{	ext{moles}}{	ext{molarity}} = \frac{0.04 \ mol}{0.1 \ M} = 0.4 \ L = 400 \ mL$.

$P_4O_6$ reacts with water according to the equation $P_4O_6 + 6H_2O \to 4H_3PO_3$. Calculate the volume of $0.1 \ M$ $NaOH$ solution required to neutralize the acid formed by dissolving $1.1 \ g$ of $P_4O_6$ in $H_2O$. (in $mL$)

Similar Questions

The amount of $Na_2S_2O_3 \cdot 5H_2O$ required to completely reduce $100 \, mL$ of $0.25 \, N$ iodine solution is $.... \, g$.

The $NaNO_3$ weighed out to make $50 \ mL$ of an aqueous solution containing $70.0 \ mg$ $Na^{+}$ per $mL$ is $...... \ g$.
(Rounded off to the nearest integer) [Given : Atomic weight in $g \ mol^{-1}$ - $Na : 23$; $N : 14$; $O : 16$]

The volume of $0.6 \, M$ $NaOH$ required to neutralize $30 \, cm^3$ of $0.4 \, M$ $HCl$ is ........ $cm^3$.

$100 \ mL$ of $0.1 \ N$ hypo solution is decolourised by the iodine liberated from the addition of $x \ g$ of crystalline copper sulphate to an excess of $KI$. The value of $x$ is ............. $g$ (molecular weight of $CuSO_4 \cdot 5H_2O$ is $250$).

$150 \ g$ $CaCO_3$ sample was taken. On its complete decomposition $56 \ g$ $CaO$ is produced. The $\%$ purity of the sample is .............. $\%$

Vedclass Test Series

Exam Paper Generator

Online Exam Module