100 mL of 0.1 N hypo solution is decolouris | vedclass

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(C) The chemical reactions involved are:$2CuSO_4 + 4KI 	o 2CuI_2 + 2K_2SO_4$$2CuI_2 	o Cu_2I_2 + I_2$$I_2 + 2Na_2S_2O_3 	o 2NaI + Na_2S_4O_6$From t

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$2.5$

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(C) The chemical reactions involved are:$2CuSO_4 + 4KI 	o 2CuI_2 + 2K_2SO_4$$2CuI_2 	o Cu_2I_2 + I_2$$I_2 + 2Na_2S_2O_3 	o 2NaI + Na_2S_4O_6$From the stoichiometry,$1 	ext{ mole of } CuSO_4 \cdot 5H_2O$ produces $0.5 	ext{ mole of } I_2$,which reacts with $1 	ext{ mole of } Na_2S_2O_3$ (hypo).Thus,the equivalent weight of $CuSO_4 \cdot 5H_2O$ is equal to its molecular weight $(250 \ g/eq)$.Equivalents of hypo = Equivalents of $CuSO_4 \cdot 5H_2O$$N 	imes V(L) = \frac{x}{	ext{Equivalent weight}}$$0.1 	imes \frac{100}{1000} = \frac{x}{250}$$0.01 = \frac{x}{250}$$x = 2.5 \ g$.

$100 \ mL$ of $0.1 \ N$ hypo solution is decolourised by the iodine liberated from the addition of $x \ g$ of crystalline copper sulphate to an excess of $KI$. The value of $x$ is ............. $g$ (molecular weight of $CuSO_4 \cdot 5H_2O$ is $250$).

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