What is the dimensional formula for the ratio | vedclass

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Question

(A) Angular momentum $(L)$ is defined as $L = r 	imes p$,where $r$ is the position vector and $p$ is the linear momentum.The dimensional formula for

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$M^{0}L^{1}T^{0}$

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(A) Angular momentum $(L)$ is defined as $L = r 	imes p$,where $r$ is the position vector and $p$ is the linear momentum.The dimensional formula for angular momentum $(L)$ is $[M^{1}L^{2}T^{-1}]$.The dimensional formula for linear momentum $(p)$ is $[M^{1}L^{1}T^{-1}]$.Taking the ratio of angular momentum to linear momentum: $\frac{L}{p} = \frac{[M^{1}L^{2}T^{-1}]}{[M^{1}L^{1}T^{-1}]}$.Simplifying the dimensions: $\frac{M^{1-1}L^{2-1}T^{-1-(-1)}}{1} = M^{0}L^{1}T^{0}$.Thus,the dimensional formula is $[L^{1}]$,which represents the dimension of length.

What is the dimensional formula for the ratio of angular momentum to linear momentum?

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