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Question

(A) Impulse $(J)$ is defined as the product of force $(F)$ and the time interval $(\Delta t)$ for which the force acts.Mathematically,$J = F 	imes \D

Vedclass · Accepted Answer

$M^1 L^1 T^{-1}$

Vedclass · Answer

(A) Impulse $(J)$ is defined as the product of force $(F)$ and the time interval $(\Delta t)$ for which the force acts.Mathematically,$J = F 	imes \Delta t$.The dimensional formula for force $(F)$ is $[M^1 L^1 T^{-2}]$.The dimensional formula for time $(\Delta t)$ is $[T^1]$.Therefore,the dimensional formula for impulse is $[M^1 L^1 T^{-2}] 	imes [T^1] = [M^1 L^1 T^{-1}]$.Thus,the correct dimensional formula is $[M^1 L^1 T^{-1}]$.

Column-$I$	Column-$II$
$(A)$ Electrical resistance	$(p)$ $M L^3 T^{-3} A^{-2}$
$(B)$ Electrical potential	$(q)$ $M L^2 T^{-3} A^{-2}$
$(C)$ Specific resistance	$(r)$ $M L^2 T^{-3} A^{-1}$
$(D)$ Specific conductance	$(s)$ None of these

Write the dimensional formula for impulse of a force.

Similar Questions

Match the following two columns:

Column-$I$ Column-$II$

$(A)$ Electrical resistance $(p)$ $M L^3 T^{-3} A^{-2}$

$(B)$ Electrical potential $(q)$ $M L^2 T^{-3} A^{-2}$

$(C)$ Specific resistance $(r)$ $M L^2 T^{-3} A^{-1}$

$(D)$ Specific conductance $(s)$ None of these

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