Complete the following reaction:CH_3CH_2-O-C( | vedclass

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(A) The reaction of an ether with concentrated $HI$ proceeds via an $S_N1$ mechanism when one of the alkyl groups is tertiary.In the given ether,$CH_3

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$CH_3CH_2OH + CH_3-CI(CH_3)-CH_2CH_3$

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(A) The reaction of an ether with concentrated $HI$ proceeds via an $S_N1$ mechanism when one of the alkyl groups is tertiary.In the given ether,$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3$,the group attached to the oxygen is a tertiary alkyl group ($2$-methyl$-2-$butyl group).The protonation of the ether oxygen by $HI$ forms an oxonium ion.Then,the $C-O$ bond breaks to form a stable tertiary carbocation $(CH_3)_2C^+-CH_2CH_3$ and ethanol $(CH_3CH_2OH)$.The iodide ion $(I^-)$ then attacks the tertiary carbocation to form $2-$iodo$-2-$methylbutane.Thus,the products are ethanol $(CH_3CH_2OH)$ and $2-$iodo$-2-$methylbutane $(CH_3-CI(CH_3)-CH_2CH_3)$.

Complete the following reaction:
$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3 + \text{conc. } HI \to (?)$

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Complete the following reaction:$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3 + \text{conc. } HI \to (?)$