Ethanol reacts with H_2SO_4 at 140^circ C to | vedclass

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(C) When ethanol $(CH_3CH_2OH)$ is heated with concentrated $H_2SO_4$ at $140^\circ C$ $(413 \ K)$,it undergoes intermolecular dehydration to form die

Vedclass · Accepted Answer

Ethoxy ethane

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(C) When ethanol $(CH_3CH_2OH)$ is heated with concentrated $H_2SO_4$ at $140^\circ C$ $(413 \ K)$,it undergoes intermolecular dehydration to form diethyl ether (ethoxy ethane).The reaction is as follows:$2CH_3CH_2OH \xrightarrow{conc. H_2SO_4, 140^\circ C} CH_3CH_2-O-CH_2CH_3 + H_2O$Mechanism:$1$. Protonation of ethanol: $CH_3CH_2OH + H^+ \rightarrow CH_3CH_2OH_2^+$$2$. Nucleophilic attack: $CH_3CH_2OH_2^+ + CH_3CH_2OH \rightarrow CH_3CH_2-O^+(H)-CH_2CH_3 + H_2O$$3$. Deprotonation: $CH_3CH_2-O^+(H)-CH_2CH_3 \rightarrow CH_3CH_2-O-CH_2CH_3 + H^+$

Ethanol reacts with $H_2SO_4$ at $140^\circ C$ to form

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