Explain: Propan-$2$-ol is symmetric and achiral. (Diagram required)

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Propan-$2$-ol $(CH_3CHOHCH_3)$ is a symmetric molecule because it contains a plane of symmetry.
The structure shows that the central carbon atom is not bonded to four different groups. It has two identical $-CH_3$ groups attached to the $C^2$ atom,which makes propan-$2$-ol symmetric and therefore an achiral molecule.
Rotating the mirror image $(B)$ of structure $(A)$ by $180^{\circ}$ yields structure $(C)$. Structures $(C)$ and $(A)$ are superimposable on each other. Thus,propan-$2$-ol is an achiral molecule.
Therefore,since propan-$2$-ol is symmetric and achiral,it does not exhibit optical activity.

Explore More

Similar Questions

Which of the following represent$(s)$ the enantiomer of $Y$?

The correct statement$(s)$ about the compound $H_3C-CH(OH)-CH=CH-CH(OH)-CH_3$ $(X)$ is(are):
$(A)$ The total number of stereoisomers possible for $X$ is $6$.
$(B)$ The total number of diastereomers possible for $X$ is $3$.
$(C)$ If the stereochemistry about the double bond in $X$ is trans,the number of enantiomers possible for $X$ is $4$.
$(D)$ If the stereochemistry about the double bond in $X$ is cis,the number of enantiomers possible for $X$ is $2$.

Why is $Meso-tartaric$ acid optically inactive?

The absolute configurations of the following compounds are respectively:

Which of the following compounds is not chiral?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo