(A) Let the oxidation state of $Cu$ be $x$. The oxidation state of the cyanide ion $(CN^-)$ is $-1$. The overall charge on the complex $[Cu(CN)_4]^{3-

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(A) Let the oxidation state of $Cu$ be $x$. The oxidation state of the cyanide ion $(CN^-)$ is $-1$. The overall charge on the complex $[Cu(CN)_4]^{3-}$ is $-3$. Setting up the equation: $x + 4(-1) = -3$. $x - 4 = -3$. $x = -3 + 4 = +1$. Therefore,the oxidation state of $Cu$ is $+1$.