If the mass and radius of a planet are double | vedclass

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(B) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.For Earth,$g_e = \frac{GM_e}{R_e^2}$.For the given pla

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$g/2$

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(B) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$.For Earth,$g_e = \frac{GM_e}{R_e^2}$.For the given planet,the mass $M_p = 2M_e$ and the radius $R_p = 2R_e$.Substituting these values into the formula for the planet's gravity $g_p$:$g_p = \frac{G(2M_e)}{(2R_e)^2}$$g_p = \frac{2GM_e}{4R_e^2}$$g_p = \frac{1}{2} \left( \frac{GM_e}{R_e^2} \right)$Since $g_e = \frac{GM_e}{R_e^2}$,we get $g_p = \frac{g_e}{2}$.Thus,the acceleration due to gravity on the planet is half that of Earth.

If the mass and radius of a planet are double those of the Earth,what will be the acceleration due to gravity on this planet compared to the acceleration due to gravity on Earth?

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