If overrightarrow{A} = 2widehat{i} - 2widehat | vedclass

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(A) The dot product of two vectors $\overrightarrow{A} = A_x\widehat{i} + A_y\widehat{j} + A_z\widehat{k}$ and $\overrightarrow{B} = B_x\widehat{i} +

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(A) The dot product of two vectors $\overrightarrow{A} = A_x\widehat{i} + A_y\widehat{j} + A_z\widehat{k}$ and $\overrightarrow{B} = B_x\widehat{i} + B_y\widehat{j} + B_z\widehat{k}$ is given by $\overrightarrow{A} \cdot \overrightarrow{B} = A_x B_x + A_y B_y + A_z B_z$.Given $\overrightarrow{A} = 2\widehat{i} - 2\widehat{j} + 0\widehat{k}$ and $\overrightarrow{B} = 0\widehat{i} + 0\widehat{j} + 2\widehat{k}$.Substituting the components: $\overrightarrow{A} \cdot \overrightarrow{B} = (2)(0) + (-2)(0) + (0)(2)$.$\overrightarrow{A} \cdot \overrightarrow{B} = 0 + 0 + 0 = 0$.

If $\overrightarrow{A} = 2\widehat{i} - 2\widehat{j}$ and $\overrightarrow{B} = 2\widehat{k}$,then find the dot product $\overrightarrow{A} \cdot \overrightarrow{B}$.

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