What happens to the direction and magnitude of a vector when it is multiplied by a positive and a negative scalar $\lambda$?
- APositive $\lambda$: Same direction,magnitude scaled by $\lambda$; Negative $\lambda$: Opposite direction,magnitude scaled by $|\lambda|$.
- BPositive $\lambda$: Opposite direction,magnitude scaled by $\lambda$; Negative $\lambda$: Same direction,magnitude scaled by $|\lambda|$.
- CPositive $\lambda$: Same direction,magnitude remains same; Negative $\lambda$: Opposite direction,magnitude remains same.
- DPositive $\lambda$: Opposite direction,magnitude scaled by $\lambda$; Negative $\lambda$: Opposite direction,magnitude scaled by $|\lambda|$.
Explore More
Similar Questions
$\hat{i} \cdot (\hat{j} \times \hat{k}) + \hat{j} \cdot (\hat{k} \times \hat{i}) + \hat{k} \cdot (\hat{i} \times \hat{j}) = $
Easy
View SolutionThe dot product of unit vectors $\hat{n}_1$ and $\hat{n}_2$ that are parallel to $5 \hat{i}+12 \hat{j}$ and $3 \hat{i}+4 \hat{j}$ respectively is
The angle between the two vectors $(2\hat{i} + 3\hat{j} + \hat{k})$ and $(-3\hat{i} + 6\hat{k})$ is ...... $^\circ$.
Medium
View SolutionLet $|\vec{A}_1| = 3$,$|\vec{A}_2| = 5$,and $|\vec{A}_1 + \vec{A}_2| = 5$. The value of $(2\vec{A}_1 + 3\vec{A}_2) \cdot (3\vec{A}_1 - 2\vec{A}_2)$ is (in $.5$)
DifficultJEE MAIN 2019
View SolutionTwo vectors $\vec{A}$ and $\vec{B}$ are at right angles to each other,when
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo