$p-$Dichlorobenzene has a higher $m.p.$ than those of $o-$ and $m-$ isomers. Discuss.
(N/A) $p-$Dichlorobenzene is more symmetrical than $o-$ and $m-$ isomers.
Due to this symmetry,it fits more closely than $o-$ and $m-$ isomers in the crystal lattice.
Therefore,more energy is required to break the crystal lattice of $p-$dichlorobenzene.
As a result,$p-$Dichlorobenzene has a higher melting point and lower solubility than $o-$ and $m-$ isomers.
Due to this symmetry,it fits more closely than $o-$ and $m-$ isomers in the crystal lattice.
Therefore,more energy is required to break the crystal lattice of $p-$dichlorobenzene.
As a result,$p-$Dichlorobenzene has a higher melting point and lower solubility than $o-$ and $m-$ isomers.
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