1 mole of MnO_4^{2-} in neutral aqueous medi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The disproportionation reaction of manganate ion $(MnO_4^{2-})$ in a neutral aqueous medium is given by: $3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^-

Vedclass · Accepted Answer

$2/3 \ mole$ of $MnO_4^-$ and $1/3 \ mole$ of $MnO_2$

Vedclass · Answer

(A) The disproportionation reaction of manganate ion $(MnO_4^{2-})$ in a neutral aqueous medium is given by: $3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^- + MnO_2 + 2H_2O$ From the stoichiometry of the balanced equation,$3 \ moles$ of $MnO_4^{2-}$ produce $2 \ moles$ of $MnO_4^-$ and $1 \ mole$ of $MnO_2$. Therefore,$1 \ mole$ of $MnO_4^{2-}$ will produce $\frac{2}{3} \ mole$ of $MnO_4^-$ and $\frac{1}{3} \ mole$ of $MnO_2$.

$1 \ mole$ of $MnO_4^{2-}$ in neutral aqueous medium disproportionates to:

Similar Questions

Identify the correct statement for the following reaction: $3 Br_2 + 6 CO_3^{2-} + 3 H_2O \rightarrow 5 Br^{-} + BrO_3^- + 6 HCO_3^-$

Fluorine reacts with ice and results in the change: $H_2O_{(s)} + F_{2(g)} \to HF_{(g)} + HOF_{(g)}$. Justify that this reaction is a redox reaction.

Nitrous acid was disproportionated to form water,$HNO_3$ and $X$. In another reaction,sodium nitrite was reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$,water and $Y$. What are $X$ and $Y$ respectively?

Which of the following does not show a disproportionation reaction?

Which of the following is not a disproportionation reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module