Nitrous acid was disproportionated to form wa | vedclass

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(B) Nitrous acid $(HNO_2)$ undergoes disproportionation to form nitric acid $(HNO_3)$,water $(H_2O)$,and nitric oxide $(NO)$. The balanced chemical eq

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$NO, NO$

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(B) Nitrous acid $(HNO_2)$ undergoes disproportionation to form nitric acid $(HNO_3)$,water $(H_2O)$,and nitric oxide $(NO)$. The balanced chemical equation is: $3 HNO_2 \longrightarrow HNO_3 + H_2O + 2 NO$. Thus,$X = NO$. In the second reaction,sodium nitrite $(NaNO_2)$ reacts with sulfuric acid $(H_2SO_4)$ to form sodium bisulfate $(NaHSO_4)$,nitric acid $(HNO_3)$,water $(H_2O)$,and nitric oxide $(NO)$. The balanced chemical equation is: $2 NaNO_2 + H_2SO_4 \longrightarrow NaHSO_4 + HNO_3 + H_2O + NO$. Thus,$Y = NO$.

Nitrous acid was disproportionated to form water,$HNO_3$ and $X$. In another reaction,sodium nitrite was reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$,water and $Y$. What are $X$ and $Y$ respectively?

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