{}^{238}U has 92 protons and 238 nucleons. It | vedclass

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(B) An alpha particle is a helium nucleus,represented as ${}_{2}^{4}He$.When a nucleus undergoes alpha decay,its atomic number $(Z)$ decreases by $2$

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${}_{90}^{234}Th$

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(B) An alpha particle is a helium nucleus,represented as ${}_{2}^{4}He$.When a nucleus undergoes alpha decay,its atomic number $(Z)$ decreases by $2$ and its mass number $(A)$ decreases by $4$.The decay equation is:${}_{92}^{238}U \longrightarrow {}_{Z}^{A}X + {}_{2}^{4}He$Equating the mass numbers: $238 = A + 4 \implies A = 234$.Equating the atomic numbers: $92 = Z + 2 \implies Z = 90$.The element with atomic number $90$ is Thorium $(Th)$.Therefore,the daughter nucleus is ${}_{90}^{234}Th$.

${}^{238}U$ has $92$ protons and $238$ nucleons. It decays by emitting an alpha particle and becomes:

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