Assertion : Angle of repose is equal to the a | vedclass

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Question

$\begin{array}{l}
The\,{m{maximum}}\,value\,of\,static\,friction\,up\
to\,which\,body\,does\,not\,move\,is\,called\,\
{m{limiting}}\,friction

Vedclass · Accepted Answer

If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

Vedclass · Answer

$\begin{array}{l}
The\,{m{maximum}}\,value\,of\,static\,friction\,up\
to\,which\,body\,does\,not\,move\,is\,called\,\
{m{limiting}}\,friction.\
\,\,\,\,\,\,\,\,\,Angle\,of\,repose\,is\,defined\,as\,the\,angle\
\,\,\,\,\,\,\,\,\,\,of\,the\,inclined\,plane\,with\,horizontal\
\,\,\,\,\,\,\,\,\,\,such\,that\,a\,body\,placed\,on\,it\,is\,just\,\
\,\,\,\,\,\,\,\,\,\,begins\,to\,slide.\
\,\,\,\,\,\,\,\,\,In\,{m{limiting}}\,{m{condition,}}\
\,\,\,\,\,\,\,\,\,F = mg\sin \alpha \,and\,R = mg\cos \alpha \
\,\,\,\,\,\,\,\,\,where\,\alpha  - angle\,of\,repose.
\end{array}$

$\begin{array}{l}
\,\,So\,\frac{F}{R} = 	an \alpha \
\,\,\,\,\,\,\,\,\,\,	herefore \frac{F}{R} = {\mu _2} = 	an 	heta  = 	an \alpha \,\,\,\left( {	an 	heta  = {\mu _s}} ight)\
\,\,\,\,\,\,\,\,\,\,or\,	heta  = \alpha \
\,\,\,\,\,\,\,\,\,\,i.e,.\,angle\,of\,friciton\, = \,angle\,of\,repose.
\end{array}$

$Assertion$ : Angle of repose is equal to the angle of limiting friction.
$Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.

Similar Questions

A block of weight $W$ is kept on a rough horizontal surface (friction coefficient $\mu$). Two forces $W/2$ each are applied as shown in the figure. Choose the $CORRECT$ statement :-

A body of mass $1\, kg$ rests on a horizontal floor with which it has a coefficient of static friction $\frac{1}{\sqrt{3}}$. It is desired to make the body move by applying the minimum possible force $F\, N$. The value of $F$ will be the Nearest Integer) [Take $g =10 \,ms ^{-2}$ ]

Maximum value of static friction is called

$Assertion$ : Angle of repose is equal to the angle of limiting friction. $Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.

Similar Questions

A block of weight $W$ is kept on a rough horizontal surface (friction coefficient $\mu$). Two forces $W/2$ each are applied as shown in the figure. Choose the $CORRECT$ statement :-

A body of mass $1\, kg$ rests on a horizontal floor with which it has a coefficient of static friction $\frac{1}{\sqrt{3}}$. It is desired to make the body move by applying the minimum possible force $F\, N$. The value of $F$ will be the Nearest Integer) [Take $g =10 \,ms ^{-2}$ ]

Maximum value of static friction is called

$Assertion$ : Angle of repose is equal to the angle of limiting friction.
$Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.