$pH$ of $0.1 \ M$ solution of a weak acid $(HA)$ is $4.50$. It is neutralized with $NaOH$ solution to decrease the acid content to half. The $pH$ of the resulting solution is:

  • A
    $4.50$
  • B
    $8$
  • C
    $7$
  • D
    $10$

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