The number of peroxide bonds in the perxenate | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the perxenate ion $[XeO_6]^{4-}$,the oxidation state of Xenon $(Xe)$ is calculated as follows: $x + 6(-2) = -4$,which gives $x = +8$. Since the

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) In the perxenate ion $[XeO_6]^{4-}$,the oxidation state of Xenon $(Xe)$ is calculated as follows: $x + 6(-2) = -4$,which gives $x = +8$. Since the maximum oxidation state of Xenon is $+8$,all oxygen atoms are bonded to Xenon via single bonds. The structure of $[XeO_6]^{4-}$ is an octahedral geometry where Xenon is at the center and six oxygen atoms are attached to it. There are no oxygen-oxygen $(O-O)$ bonds present in this structure. Therefore,the number of peroxide bonds is $0$.

The number of peroxide bonds in the perxenate ion $[XeO_6]^{4-}$ is ........

Similar Questions

Find the product of the following reaction,when $Xe$ is taken in excess:
$Xe_{(g)} + F_{2(g)} \longrightarrow ?$

Which of the following has zero valency?

Inert gases are named because of their inertness towards reactivity. Identify the incorrect statement about them.

Which of the following has the square planar structure?

Xenon tetrafluoride,$XeF_4$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module