(A) $XeF_4$ has a square planar structure because it has $4$ bond pairs and $2$ lone pairs on the central $Xe$ atom,resulting in $sp^3d^2$ hybridizati

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(A) $XeF_4$ has a square planar structure because it has $4$ bond pairs and $2$ lone pairs on the central $Xe$ atom,resulting in $sp^3d^2$ hybridization.$NH_4^+$,$BF_4^-$,and $CCl_4$ all have $4$ bond pairs and $0$ lone pairs,resulting in $sp^3$ hybridization and a tetrahedral structure.