Oxidation states of P in H_{4}P_{2}O_{5}, H_{ | vedclass

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(D) The oxidation state of $P$ $(x)$ is calculated as follows:For $H_{4}P_{2}O_{5}: 4(+1) + 2x + 5(-2) = 0$ $\Rightarrow 2x - 6 = 0$ $\Rightarrow x =

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$+3, +4, +5$

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(D) The oxidation state of $P$ $(x)$ is calculated as follows:For $H_{4}P_{2}O_{5}: 4(+1) + 2x + 5(-2) = 0$ $\Rightarrow 2x - 6 = 0$ $\Rightarrow x = +3$For $H_{4}P_{2}O_{6}: 4(+1) + 2x + 6(-2) = 0$ $\Rightarrow 2x - 8 = 0$ $\Rightarrow x = +4$For $H_{4}P_{2}O_{7}: 4(+1) + 2x + 7(-2) = 0$ $\Rightarrow 2x - 10 = 0$ $\Rightarrow x = +5$Thus,the oxidation states are $+3, +4, +5$.

Oxidation states of $P$ in $H_{4}P_{2}O_{5}, H_{4}P_{2}O_{6}, H_{4}P_{2}O_{7}$ are respectively:

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