The pH of a solution produced when an aqueous | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the first solution,$pH = 6$,so $[H^{+}]_1 = 10^{-6} \ M$.For the second solution,$pH = 3$,so $[H^{+}]_2 = 10^{-3} \ M$.When equal volumes $(V)

Vedclass · Accepted Answer

$3.3$

Vedclass · Answer

(A) For the first solution,$pH = 6$,so $[H^{+}]_1 = 10^{-6} \ M$.For the second solution,$pH = 3$,so $[H^{+}]_2 = 10^{-3} \ M$.When equal volumes $(V)$ are mixed,the total volume becomes $2V$.The total concentration of $[H^{+}]$ is given by: $[H^{+}]_{total} = \frac{[H^{+}]_1 V + [H^{+}]_2 V}{2V} = \frac{10^{-6} + 10^{-3}}{2}$.$[H^{+}]_{total} = \frac{0.001001}{2} = 5.005 	imes 10^{-4} \ M$.The $pH$ is calculated as: $pH = -\log(5.005 	imes 10^{-4}) = 4 - \log(5.005) \approx 4 - 0.7 = 3.3$.

The $pH$ of a solution produced when an aqueous solution of $pH$ $6$ is mixed with an equal volume of an aqueous solution of $pH$ $3$ is about:

Similar Questions

Calculate the volume of $0.1 \ M \ NaOH$ required to complete the neutralization of $300 \ mL$ of $HCl$ solution having $pH = 2.25$. (in $mL$)

The $pH$ of a $10^{-10} \ M$ $HCl$ solution is approximately

The $pH$ of a solution obtained by mixing $50 \ mL$ of $0.4 \ N \ HCl$ and $50 \ mL$ of $0.2 \ N \ NaOH$ is

Equal volumes of three acid solutions of $pH$ $3$,$4$ and $5$ are mixed in a vessel. What will be the $H^{+}$ ion concentration in the mixture in terms of $\times 10^{-4} \ M$?

The $pH$ of the solution obtained by mixing $100 \ mL$ of a solution of $pH=3$ with $400 \ mL$ of a solution of $pH=4$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module