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(D) Propanoic acid $(CH_3CH_2COOH)$ is a carboxylic acid. To convert a carboxylic acid into a primary alcohol (propan-$1$-ol,$CH_3CH_2CH_2OH$),a stron

Vedclass · Accepted Answer

$LiAlH_4$

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(D) Propanoic acid $(CH_3CH_2COOH)$ is a carboxylic acid. To convert a carboxylic acid into a primary alcohol (propan-$1$-ol,$CH_3CH_2CH_2OH$),a strong reducing agent is required. $LiAlH_4$ (Lithium aluminium hydride) is a powerful reducing agent capable of reducing carboxylic acids directly to primary alcohols. Other reagents like $KMnO_4$ are oxidizing agents,while $MnO_2$ and $Cr_2O_3$ are not suitable for this specific reduction.

Which of the following reagents will convert propanoic acid to propan-$1$-ol?

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