Beryllium shows a diagonal relationship with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Beryllium $(Be)$ and Aluminum $(Al)$ exhibit a diagonal relationship due to similar charge-to-size ratios. $1$. Both $Be_2C$ and $Al_4C_3$ produce

Vedclass · Accepted Answer

$Be(OH)_2$ is basic like $Al(OH)_3$

Vedclass · Answer

(C) Beryllium $(Be)$ and Aluminum $(Al)$ exhibit a diagonal relationship due to similar charge-to-size ratios. $1$. Both $Be_2C$ and $Al_4C_3$ produce methane $(CH_4)$ upon hydrolysis. $2$. Both metals become passive towards concentrated $HNO_3$ due to the formation of an inert oxide layer. $3$. Both $Be(OH)_2$ and $Al(OH)_3$ are amphoteric in nature,not basic. Therefore,the statement that $Be(OH)_2$ is basic like $Al(OH)_3$ is incorrect. $4$. Both form complex anions: $Be$ forms beryllates $([Be(OH)_4]^{2-})$ and $Al$ forms aluminates $([Al(OH)_4]^-)$.

Beryllium shows a diagonal relationship with aluminum. Which of the following similarities is incorrect?

Similar Questions

$Ra$ (Radium) is placed at the bottom of the alkaline earth metals. Which of the following is true for this element?

Assertion $(A)$: $MgO$,$CaO$,$SrO$,and $BaO$ are insoluble in water.
Reason $(R)$: In aqueous medium,the basic strength of $MgO$,$CaO$,$SrO$,and $BaO$ increases with an increase in the atomic number of the metal.
The correct option among the following is:

$BeF_2$ is soluble in water,whereas fluorides of other alkaline earth metals are insoluble. The reason is ...

Which of the following sets represents the alkaline earth metals?

Assertion : Barium is not required for normal biological function in humans.
Reason : Barium does not show variable oxidation states.

Vedclass Test Series

Exam Paper Generator

Online Exam Module