BeF_2 is soluble in water,whereas fluorides o | vedclass

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(C) The solubility of ionic compounds in water is determined by the balance between lattice energy and hydration energy. For $BeF_2$,the hydration ene

Vedclass · Accepted Answer

The hydration energy of the $Be^{2+}$ ion is higher than its lattice energy.

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(C) The solubility of ionic compounds in water is determined by the balance between lattice energy and hydration energy. For $BeF_2$,the hydration energy of the small $Be^{2+}$ ion is significantly higher than its lattice energy,which overcomes the lattice forces and makes it soluble in water. In contrast,for other alkaline earth metal fluorides,the lattice energy dominates,making them insoluble.

Column-$I$	Column-$II$
$(a)$ Calcium	$(p)$ Crimson red
$(b)$ Barium	$(q)$ Brick red
$(c)$ Strontium	$(r)$ Apple green
-	$(s)$ Yellow

$BeF_2$ is soluble in water,whereas fluorides of other alkaline earth metals are insoluble. The reason is ...

Similar Questions

Match column-$I$ with column-$II$ :
Column-$I$ Column-$II$
$(a)$ Calcium $(p)$ Crimson red
$(b)$ Barium $(q)$ Brick red
$(c)$ Strontium $(r)$ Apple green
- $(s)$ Yellow

The setting of Plaster of Paris is associated with which of the following?

Assertion : Of the various chlorides of alkaline earth metals $BeCl_2$ is covalent in nature,whereas $MgCl_2$ and $CaCl_2$ are ionic compounds.
Reason : $Be$ is the first member of group $2$.

Which of the following sulfates is insoluble in water?

Which of the following ions has the largest heat of hydration?

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