Hydrolysis of one mole of peroxodisulphuric acid $(H_2S_2O_8)$ yields:
- ATwo moles of sulphuric acid
- BTwo moles of peroxomonosulphuric acid
- COne mole of sulphuric acid and one mole of peroxomonosulphuric acid
- DOne mole of sulphuric acid,one mole of peroxomonosulphuric acid,and one mole of hydrogen peroxide
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The equation $H_2S + H_2O_2 \to S + 2H_2O$ represents:
Medium
View SolutionIn which of the following reactions does $H_2O_2$ act as an oxidising agent (either in acidic,alkaline,or neutral medium)?
$(i)$ $2Fe^{2+} + H_2O_2 \rightarrow$
$(ii)$ $2MnO_4^{-} + 6H^{+} + 5H_2O_2 \rightarrow$
$(iii)$ $I_2 + H_2O_2 + 2OH^{-} \rightarrow$
$(iv)$ $Mn^{2+} + H_2O_2 \rightarrow$
$(i)$ $2Fe^{2+} + H_2O_2 \rightarrow$
$(ii)$ $2MnO_4^{-} + 6H^{+} + 5H_2O_2 \rightarrow$
$(iii)$ $I_2 + H_2O_2 + 2OH^{-} \rightarrow$
$(iv)$ $Mn^{2+} + H_2O_2 \rightarrow$
In which of the following reactions does $H_2O_2$ act as a reductant?
Medium
View SolutionThe product$(s)$ formed when $H_2O_2$ reacts with disodium hydrogen phosphate is
The correct statements from the following are:
$i$. $Ca(OH)_2$ is used in Clark's method of removal of temporary hardness of water.
$ii$. $100 \ mL$ of $10$ vol $H_2O_2$ on complete decomposition liberates $1 \ L$ of oxygen at $STP$.
$iii$. Urea can be added to the solution of $H_2O_2$ as stabilizer.
$i$. $Ca(OH)_2$ is used in Clark's method of removal of temporary hardness of water.
$ii$. $100 \ mL$ of $10$ vol $H_2O_2$ on complete decomposition liberates $1 \ L$ of oxygen at $STP$.
$iii$. Urea can be added to the solution of $H_2O_2$ as stabilizer.
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