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(D) $i$. $Ca(OH)_2$ (slaked lime) is added to hard water in Clark's method to precipitate calcium and magnesium bicarbonates as carbonates,effectively

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$i, ii, iii$

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(D) $i$. $Ca(OH)_2$ (slaked lime) is added to hard water in Clark's method to precipitate calcium and magnesium bicarbonates as carbonates,effectively removing temporary hardness. This statement is correct.$ii$. $10$ vol $H_2O_2$ means $1 \ mL$ of $H_2O_2$ solution gives $10 \ mL$ of $O_2$ at $STP$. Therefore,$100 \ mL$ of $10$ vol $H_2O_2$ gives $100 	imes 10 = 1000 \ mL = 1 \ L$ of $O_2$ at $STP$. This statement is correct.$iii$. $H_2O_2$ is an unstable liquid and decomposes slowly on exposure to light or on standing. Urea,acetanilide,or phosphoric acid are commonly added in small amounts as stabilizers to prevent its decomposition. This statement is correct.Thus,all statements $i, ii,$ and $iii$ are correct.

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The correct statements from the following are:$i$. $Ca(OH)_2$ is used in Clark's method of removal of temporary hardness of water.$ii$. $100 \ mL$ of $10$ vol $H_2O_2$ on complete decomposition liberates $1 \ L$ of oxygen at $STP$.$iii$. Urea can be added to the solution of $H_2O_2$ as stabilizer.