In which of the following reactions does $H_2O_2$ act as a reducing agent?
- A$PbO_{2(s)} + H_2O_{2(aq)} \to PbO_{(s)} + H_2O_{(l)} + O_{2(g)}$
- B$Na_2SO_{3(aq)} + H_2O_{2(aq)} \to Na_2SO_{4(aq)} + H_2O_{(l)}$
- C$2KI_{(aq)} + H_2O_{2(aq)} \to 2KOH_{(aq)} + I_{2(s)}$
- D$KNO_{2(aq)} + H_2O_{2(aq)} \to KNO_{3(aq)} + H_2O_{(l)}$
Explore More
Similar Questions
Give uses of Hydrogen peroxide $(H_2O_2)$.
Medium
View SolutionBy which of the following methods,$H_2O_2$ cannot be synthesized?
$20$ volume $H_2O_2$ solution has a strength of about $........... \%$
Medium
View SolutionGiven below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R.$
Assertion $A:$ The dihedral angle in $H_{2}O_{2}$ in the gaseous phase is $90.2^{\circ}$ and in the solid phase is $111.5^{\circ}$.
Reason $R:$ The change in dihedral angle in the solid and gaseous phases is due to the difference in the intermolecular forces.
Choose the most appropriate answer from the options given below for $A$ and $R$.
Assertion $A:$ The dihedral angle in $H_{2}O_{2}$ in the gaseous phase is $90.2^{\circ}$ and in the solid phase is $111.5^{\circ}$.
Reason $R:$ The change in dihedral angle in the solid and gaseous phases is due to the difference in the intermolecular forces.
Choose the most appropriate answer from the options given below for $A$ and $R$.
DifficultJEE MAIN 2021
View SolutionThe volume concentration of hydrogen peroxide having $6.8 \%$ concentration will be
DifficultMHT CET 2012
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo