20 volume H_2O_2 solution has a strength of a | vedclass

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(B) The decomposition of $H_2O_2$ is given by: $2H_2O_2 \rightarrow 2H_2O + O_2$.$68 \, g$ of $H_2O_2$ produces $22.4 \, L$ of $O_2$ at $N.T.P$.Theref

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The decomposition of $H_2O_2$ is given by: $2H_2O_2 ightarrow 2H_2O + O_2$.$68 \, g$ of $H_2O_2$ produces $22.4 \, L$ of $O_2$ at $N.T.P$.Therefore,$1 \, L$ of $O_2$ is produced by $\frac{68}{22.4} \, g$ of $H_2O_2$.For a $20$ volume solution,$1 \, L$ of $H_2O_2$ solution produces $20 \, L$ of $O_2$.Mass of $H_2O_2$ in $1 \, L$ of solution $= \frac{68}{22.4} 	imes 20 \approx 60.71 \, g$.Strength in percentage $(\% \, w/v) = \frac{	ext{mass of solute in } g}{	ext{volume of solution in } mL} 	imes 100$.Strength $= \frac{60.71 \, g}{1000 \, mL} 	imes 100 \approx 6.07 \%$.Thus,the strength is approximately $6 \%$.

$20$ volume $H_2O_2$ solution has a strength of about $........... \%$

Similar Questions

In which of the following reactions is $H_2O_2$ acting as a reducing agent?

Which of the following statements is incorrect?

Assertion $:$ Amount of $H_2O_2$ in a sample can be determined by treating $H_2O_2$ solution with $KI$ and followed by titration of liberated $I_2$ with sodium thiosulphate.
Reason $:$ In this titration,an intense blue colour appears which disappears at the end point.

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
${H_2}{\underline{S}}_2{O_8} + {H_2}O \longrightarrow {H_2}S{O_4} + {H_2}O_2$

The decomposition of $H_2O_2$ can be prevented by adding which of the following?

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