When $He$ gas is expanded into a vacuum,a heating effect is observed. What is the reason for this?
- A$He$ is an ideal gas
- B$He$ is an inert gas
- CThe inversion temperature of $He$ is very low
- DThe boiling point of $He$ is very low
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$A$ gas that follows Boyle's law,Charle's law and Avogadro's law is called an ideal gas. Under what conditions does a real gas behave ideally?
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View SolutionThe following data is obtained for one mole of a gas. The gas deviates from ideal behavior in the pressure (in bar) range:
$P \text{ (bar)}$ $\frac{PV}{RT}$ $1$ $1$ $2$ $1$ $3$ $1$ $3.1$ $1.2$ $3.5$ $1.4$ $4.0$ $1.5$
| $P \text{ (bar)}$ | $\frac{PV}{RT}$ |
|---|---|
| $1$ | $1$ |
| $2$ | $1$ |
| $3$ | $1$ |
| $3.1$ | $1.2$ |
| $3.5$ | $1.4$ |
| $4.0$ | $1.5$ |
Write the van der Waals equation.
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View SolutionWhen does a real gas behave like an ideal gas?
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View SolutionThe cooling in a refrigerator is due to
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