When a non-volatile,non-electrolyte solute is dissolved in a solvent,the vapor pressure of the solution decreases by $8\%$. The mole fraction of the solute is .............

Why is the vapour pressure of an aqueous solution of glucose lower than that of pure water?

The following graph is obtained for an ideal solution containing a non-volatile solute. The $x$- and $y$-axes represent,respectively:

When a non-volatile solute is added to the solvent,the vapour pressure of the solvent decreases by $10 \ mm \ Hg$. The mole fraction of the solute in the solution is $0.2$. What would be the mole fraction of the solvent if the decrease in vapour pressure is $20 \ mm \ Hg$?

The vapour pressure will be lowest for

Calculate the vapour pressure of pure volatile liquid $B$ $(P_B^o)$ at a given temperature if the mole fraction of liquid $B$ $(x_B)$ is $0.4$ and the vapour pressure of pure volatile liquid $A$ $(P_A^o)$ is $400 \ mm \ Hg$. The total vapour pressure of the solution is $P_{total} = 600 \ mm \ Hg$. (in $mm \ Hg$)