NaOH_{(aq)},HCl_{(aq)} and NaCl_{(aq)} concen | vedclass

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(B) $HCl$ is a strong acid,so it dissociates completely to give $[H^{+}]$ ions whose concentration is $10^{-3} \, M$. $pH = -\log([H^{+}]) = -\log(10^

Vedclass · Accepted Answer

$11, 3, 7$

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(B) $HCl$ is a strong acid,so it dissociates completely to give $[H^{+}]$ ions whose concentration is $10^{-3} \, M$. $pH = -\log([H^{+}]) = -\log(10^{-3}) = 3$. $NaOH$ is a strong base,so it dissociates completely to give $[OH^{-}]$ ions whose concentration is $10^{-3} \, M$. $pOH = -\log([OH^{-}]) = -\log(10^{-3}) = 3$. Since $pH + pOH = 14$ at $25^{\circ}C$,$pH = 14 - 3 = 11$. $NaCl$ is a salt of a strong acid and a strong base,so it is neutral in nature,thus its $pH = 7$. Therefore,the $pH$ values are $11, 3, 7$ respectively.

$NaOH_{(aq)}$,$HCl_{(aq)}$ and $NaCl_{(aq)}$ concentration of each is $10^{-3} \, M$. Their $pH$ will be respectively

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