How many optical isomers are possible for the | vedclass

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(A) The hydrogenation of $(CH_3)_2C = CH-CH_3$ ($2$-methylbut$-2-$ene) involves the addition of $H_2$ across the double bond.The product formed is $(C

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$0$

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(A) The hydrogenation of $(CH_3)_2C = CH-CH_3$ ($2$-methylbut$-2-$ene) involves the addition of $H_2$ across the double bond.The product formed is $(CH_3)_2CH-CH_2-CH_3$,which is $2$-methylbutane.In $2$-methylbutane,the structure is $CH_3-CH(CH_3)-CH_2-CH_3$.This molecule does not contain any chiral carbon atom (a carbon atom bonded to four different groups).Since there is no chiral center,the compound does not exhibit optical isomerism.Therefore,the number of optical isomers possible is $0$.

How many optical isomers are possible for the compound obtained by the hydrogenation of $(CH_3)_2C = CH-CH_3$?

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