The spin only magnetic moment value of Cr(CO) | vedclass

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Question

$Cr ( CO )_6 \Rightarrow Cr ^{\circ} \Rightarrow[ Ar ] 4 s ^1 3 d ^5$

$\Rightarrow CO =$ Strong field ligand.

$1.$ All the electrons are paired

Vedclass · Accepted Answer

$0\, BM$

Vedclass · Answer

$Cr ( CO )_6 \Rightarrow Cr ^{\circ} \Rightarrow[ Ar ] 4 s ^1 3 d ^5$

$\Rightarrow CO =$ Strong field ligand.

$1.$ All the electrons are paired due to the strong field ligand $CO$.

$2.$ So, the unpaired electrons $=0$.

$3.$ Magnetic moment $=\sqrt{0(0+2)}=0\,Bm$

The spin only magnetic moment value of $Cr(CO)_6$ is

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