R-COOH xrightarrow{text{Reagent}} R-CH_2-OHTh | vedclass

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Question

(B) The conversion of a carboxylic acid $(R-COOH)$ to a primary alcohol $(R-CH_2-OH)$ requires a strong reducing agent.$NaBH_4$ is a mild reducing age

Vedclass · Accepted Answer

$B_2H_6$

Vedclass · Answer

(B) The conversion of a carboxylic acid $(R-COOH)$ to a primary alcohol $(R-CH_2-OH)$ requires a strong reducing agent.$NaBH_4$ is a mild reducing agent and does not reduce carboxylic acids.$B_2H_6$ (diborane) is a selective and powerful reducing agent that reduces carboxylic acids to primary alcohols efficiently,while leaving other functional groups like esters or halides often unaffected.$P + HI$ is a strong reducing agent that reduces carboxylic acids to alkanes $(R-CH_3)$.$DIBAL-H$ at low temperature typically reduces esters or nitriles to aldehydes,not carboxylic acids to alcohols.Therefore,the correct reagent is $B_2H_6$.

Compound	Reaction with $Na$ metal	Reaction with $NaOH$	Reaction with $NaHCO_3$
Alcohol	$H_2$ is liberated	No reaction	No reaction
Phenol	$H_2$ is liberated	Soluble salt formed	No reaction
Carboxylic acid	$H_2$ is liberated	Soluble salt formed	$CO_2$ gas is liberated

$R-COOH \xrightarrow{\text{Reagent}} R-CH_2-OH$
The suitable reagent for the above conversion is:

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$R-COOH \xrightarrow{\text{Reagent}} R-CH_2-OH$The suitable reagent for the above conversion is: