In esterification,the OH^- ion for making H_2 | vedclass

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(A) In the esterification reaction,a carboxylic acid $(RCOOH)$ reacts with an alcohol $(R'OH)$ in the presence of an acid catalyst to form an ester $(

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Acid

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(A) In the esterification reaction,a carboxylic acid $(RCOOH)$ reacts with an alcohol $(R'OH)$ in the presence of an acid catalyst to form an ester $(RCOOR')$ and water $(H_2O)$.According to the mechanism of esterification,the $OH$ group is removed from the carboxylic acid,and the $H$ atom is removed from the alcohol.Therefore,the $OH^-$ ion (or the $OH$ part) required to form $H_2O$ comes from the carboxylic acid.

In esterification,the $OH^-$ ion for making $H_2O$ comes from

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