If the market prices of table salt (NaCl) and | vedclass

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(A) The molar mass of $NaCl = 23 + 35.5 = 58.5 \, g/mol$.Given that $1000 \, g$ of $NaCl$ costs $Rs. 4$.Therefore,the cost of $1$ mole $(58.5 \, g)$ o

Vedclass · Accepted Answer

$0.234, 10.26$

Vedclass · Answer

(A) The molar mass of $NaCl = 23 + 35.5 = 58.5 \, g/mol$.Given that $1000 \, g$ of $NaCl$ costs $Rs. 4$.Therefore,the cost of $1$ mole $(58.5 \, g)$ of $NaCl = \frac{58.5 	imes 4}{1000} = 0.234 \, Rs$.The molar mass of table sugar $(C_{12}H_{22}O_{11}) = (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342 \, g/mol$.Given that $1000 \, g$ of sugar costs $Rs. 30$.Therefore,the cost of $1$ mole $(342 \, g)$ of sugar $= \frac{342 	imes 30}{1000} = 10.26 \, Rs$.Thus,the prices are $0.234 \, Rs$ and $10.26 \, Rs$ respectively.

If the market prices of table salt $(NaCl)$ and table sugar $(C_{12}H_{22}O_{11})$ are $Rs. 4$ per $kg$ and $Rs. 30$ per $kg$ respectively,then the market price of $1$ mole of each will be,respectively,..... $Rs$.

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