Volume of a gas at STP is 1.12 times 10^{-7} | vedclass

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(B) At $STP$,$22400 \ cc$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of molecules = $\frac{	ext{Given volume}}{\

Vedclass · Accepted Answer

$3.01 	imes 10^{12}$

Vedclass · Answer

(B) At $STP$,$22400 \ cc$ of any gas contains $6.022 	imes 10^{23}$ molecules (Avogadro's number).Number of molecules = $\frac{	ext{Given volume}}{	ext{Molar volume at } STP} 	imes N_A$Number of molecules = $\frac{1.12 	imes 10^{-7} \ cc}{22400 \ cc/mol} 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol}$Number of molecules = $\frac{1.12 	imes 6.022}{22400} 	imes 10^{16} \approx 3.01 	imes 10^{12}$ molecules.

Volume of a gas at $STP$ is $1.12 \times 10^{-7} \ cc$. Calculate the number of molecules in it.

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