What is the de Broglie wavelength of a baseba | vedclass

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Question

(A) The de Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Given: Mass $(m)$ = $120 \ g = 0.120 \ kg$ Velocity $(v)$

Vedclass · Accepted Answer

$1.24 	imes 10^{-34} \ m$

Vedclass · Answer

(A) The de Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Given: Mass $(m)$ = $120 \ g = 0.120 \ kg$ Velocity $(v)$ = $44.7 \ m \ s^{-1}$ Planck's constant $(h)$ = $6.626 	imes 10^{-34} \ J \ s$ Substituting the values: $\lambda = \frac{6.626 	imes 10^{-34} \ J \ s}{0.120 \ kg 	imes 44.7 \ m \ s^{-1}}$ $\lambda = \frac{6.626 	imes 10^{-34}}{5.364} \ m$ $\lambda \approx 1.235 	imes 10^{-34} \ m$ Rounding to two decimal places,we get $\lambda \approx 1.24 	imes 10^{-34} \ m$.

What is the de Broglie wavelength of a baseball with a mass of $120 \ g$ moving at a velocity of $44.7 \ m \ s^{-1}$?

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