A 50 , L container holds 0.5 , mol of O_2 gas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The root mean square $(rms)$ speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas consta

Vedclass · Accepted Answer

Remains unchanged

Vedclass · Answer

(C) The root mean square $(rms)$ speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas constant,$T$ is the absolute temperature in Kelvin,and $M$ is the molar mass of the gas.The $rms$ speed depends only on the temperature $(T)$ and the molar mass $(M)$ of the gas.Since the temperature remains constant $(27 \, ^oC)$ and the molar mass of $O_2$ is constant,the $rms$ speed will remain unchanged regardless of the number of molecules removed.

$A$ $50 \, L$ container holds $0.5 \, mol$ of $O_2$ gas at $27 \, ^oC$ and $2 \, atm$ pressure. If half of the $O_2$ molecules are removed from the container,what happens to the $rms$ speed of the $O_2$ molecules?

Similar Questions

The ratio of the rates of diffusion of $SO_2$,$O_2$,and $CH_4$ is.....

At $STP$,write the order of root mean square speed $(u_{rms})$ for the molecules $H_2, N_2, O_2$,and $HBr$.

The ratio of most probable velocity $(u_{mp})$,average velocity $(u_{av})$,and root mean square velocity $(u_{rms})$ is:

At what temperature $(^oC)$ will the average velocity of oxygen molecules be equal to their $(rms)$ velocity at $27^oC$?

Molecular velocities of two gases at the same temperature $(T)$ are $u_{1}$ and $u_{2}$. Their masses are $m_{1}$ and $m_{2}$ respectively. Which of the following expressions is correct at temperature $T$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module